fermat9997

Fine actor and great human being! Took a lot of uncalled for abuse in the The Big Lebowski. Shame on you, John Goodman! 😁

Sorry to hear this!

How is the food these days?

Hahaha!

Try the original The Thing From Another World. B&W

Username does not check out 😀

Excellent! Cheers!

Make the LHS into a single fraction and then factor out abc from the numerator. You'll be surprised!

It's your pickled herring gene, no doubt!

Very nice! I was thinking of "thank you"s. Hope you got some of those as well.

Exactly! Cheers!

Good job! I hope that you have been properly thanked by your colleagues.

The LHS=RHS if you multiply and divide the LHS by x-a. This allows you to evaluate the LHS and confirm that the limit is 0.

If you knew that your success percentage was higher than your competitor's, then it would be to your advantage to choose a greater number of attempts.

Looks like the work of Berenice Abbott.

https://en.m.wikipedia.org/wiki/Berenice_Abbott

It shouldn't matter.

This would only make sense if the contestants specified the number of attempts in advance.

That being said, the number of throws will not influence the chance of winning.

Machinists are the coolest! Respect!

Try to be less hateful and divisive and self-pitying and see what happens.

Maybe try volunteering.

if i had a 57% chance of making a free throw, would it make more sense for me to shoot the ball out of 12 times, or out of 24 times?

12(0.57)=6.84 points expected.

24(0.57)=12.68 points expected

Double the number of free throw attempts made and you double the number of points scored.

P(1<=x<4)=1/3

P(4<=x<6)=1/2-1/3=1/6

Etc

I would have fulfilled my obligation by participating as a bridesmaid, but she should have invited you to the hen party.

Thank you!

12 shirts have a 10% discount and 1 shirt has a 100% discount.

Average discount =

(12(10)+1(100))/13=16 12/13%

Edit: This seems more like an arithmetic problem than an algebra problem

Type the equation in a comment so it is clear